Question

Write the following in algebraic form :

a) X exceeds y by 7

b) 3 taken away from two – thirds of x​

Answer 1

 x+4=9

x=9-4

x= 5

(ii) y-2=8

y=8+2

y=10

(iii) a\times10\ =\ 70a×10 = 70

(iv) \frac{b}{5}=\ 6\5b= 6 

b= 30

(v) \frac{3}{4}\times t\ =\ 15\43×t = 15 

t\ =\ 15\times\frac{4}{3}t = 15×34

t = 20

(vi) \frac{b}{5}=\ 6\5b= 6 

b\ =\ 6\ \times5\b = 6 ×5 

b = 30

(vii) \left(\frac{1}{4}\times x\right)-\ 4\ =\ 4\(41×x)− 4 = 4 

\frac{x}{4}-\ 4\ =\ 4\4x− 4 = 4 

\frac{x}{4}=4+4\4x=4+4 

x\ =\ 8\times4x = 8×4

x= 32

(viii) 6y-6 = 60

6y = 60+6

6y = 66

y\ =\ \frac{60}{6}y = 660

y = 11

(ix) \frac{z}{3}+\ 3\ =\ 30\3z+ 3 = 30 

\frac{z}{3\ }=\ 333 z= 33

z\ =\ 33\times3z = 33×3

z = 99

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