write the following in expanded form 365.08
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Step-by-step explanation:
Given,
(2x−y+z)
2
Formula,
(a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ca
⇒(2x−y+z)
2
=(2x)
2
+(−y)
2
+(z)
2
+2(2x×−y)+2(−y×z)+2(z×2x)
=4x
2
+y
2
+z
2
−4xy
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