Write the following in logarithmic form.(i) 11² = 121 (ii) (0.1)² = 0.01 (iii) aˣ = b
Answers
Answered by
8
heya here is ur answer...
1 ) 11^2 = 121
so the base should be in base only in log and the power should be in right-hand side
so it's log 121 base 11 = 2
2) (0.1)^2 = 0.01
log 0.01 base 0.1 = 2
3) a^x = b
log b base a = x
Hope this helps you
if any queries u may ask
Thank u..
1 ) 11^2 = 121
so the base should be in base only in log and the power should be in right-hand side
so it's log 121 base 11 = 2
2) (0.1)^2 = 0.01
log 0.01 base 0.1 = 2
3) a^x = b
log b base a = x
Hope this helps you
if any queries u may ask
Thank u..
Answered by
1
Solution :
************************************
We know that ,
If aⁿ = x => log x( base a ) = n
************************************
i ) 11² = 121
=> log 121 ( base 11 ) = 2
ii ) ( 0.1 )² = 0.01
=> log ( 0.01 ) ( base 0.1 ) = 2
iii ) a^x = b
=> log b ( base a ) = x
•••••
************************************
We know that ,
If aⁿ = x => log x( base a ) = n
************************************
i ) 11² = 121
=> log 121 ( base 11 ) = 2
ii ) ( 0.1 )² = 0.01
=> log ( 0.01 ) ( base 0.1 ) = 2
iii ) a^x = b
=> log b ( base a ) = x
•••••
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