write the following in set roster form: B={x:x belongs to R and x² + 3x + 2 = 0}
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answer is ( x + 1 ) ( x + 2 )
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x^2+3x+2=0
x^2+2x+x+2=0
x(x+2)+1(x+2)=0
(x+1)(x+2)=0
Therefore, x+1=0 or x+2=0
x=-1 or x=-2
Roster form would be:
x={-1,-2}
Mark me as brainliest hope it helped you.
x^2+2x+x+2=0
x(x+2)+1(x+2)=0
(x+1)(x+2)=0
Therefore, x+1=0 or x+2=0
x=-1 or x=-2
Roster form would be:
x={-1,-2}
Mark me as brainliest hope it helped you.
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