Question

write the following numbers as the difference of the square of two consecutive natural numbers 261​

Answer 1

Step-by-step explanation:

Let two consecutive natural numbers are x, x+1

ATQ

$(x + 1) {}^{2} - {x}^{2} = 261 \\ {x}^{2} + 2x + 1 - {x}^{2} = 261 \\ 2x = 261 - 1 \\ x = \frac{260}{2} \\ x = 130$

one of the number = 130

another number = x+1 = 130+1 = 131