Question

Write the following numbers as the
product of prime numbers.
2 (10
-
2 X
• 145
• 210
. 100
(2
• 168
• 225
• 288
​

Answer 1

Answer:

The prime factors of 288 are 2 and 3.

Step-by-step explanation:

Step 1: A number can be communicated as the result of its excellent parts through the course of prime factorization. A number with definitively two components, 1 and the actual number, is supposed to be an indivisible number. As a delineation, how about we utilize the number 30. Despite the fact that we know that 30 = 5 6 is definitely not an indivisible number, The factorization of the number 6 may likewise be communicated as 2 + 3, where 2 and 3 are indivisible numbers. Thus, the superb factorization of 30 is 2 3 5 with prime numbers as every one of the components.

Step 2: The excellent variables 145 are 5 and 29. The excellent factorisation of 145 is 5 × 29.

Presently, compose the number 210 as the result of its excellent variables. In this way, the excellent factorization of 210 is 2 × 3 × 5 × 7.

Thus, the great variables of 100 are composed as 2 x 2 × 5 x 5 or 2^2 x 5^2, where 2 and 5 are the indivisible numbers.

In this manner, the great variables of 168 are 2, 3 and 7. Thus, the superb factorisation of 168 is 2 × 2 × 2 × 3 × 7 or 2^3 × 3^1 × 7^1.

The great elements of 225 are 5 × 5 × 3 × 3.

288 = 2 × 2 × 2 × 2 × 2 × 3 × 3= 2^5. × 3^2. The great elements of 288 are 2 and 3.

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