Question

write the following polynomial in standard form and also write down its degree ( y²-4) (y³-5)



answer me fast please...​

Answer 1

Step-by-step explanation:

(y

(y 3

(y 3 −2)(y

(y 3 −2)(y 3

(y 3 −2)(y 3 +11)

(y 3 −2)(y 3 +11)=y

(y 3 −2)(y 3 +11)=y 3

(y 3 −2)(y 3 +11)=y 3 (y

(y 3 −2)(y 3 +11)=y 3 (y 3

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6 +11y

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6 +11y 3

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6 +11y 3 −2y

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6 +11y 3 −2y 3

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6 +11y 3 −2y 3 −22

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6 +11y 3 −2y 3 −22=y

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6 +11y 3 −2y 3 −22=y 6

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6 +11y 3 −2y 3 −22=y 6 +9y

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6 +11y 3 −2y 3 −22=y 6 +9y 3

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6 +11y 3 −2y 3 −22=y 6 +9y 3 −22

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6 +11y 3 −2y 3 −22=y 6 +9y 3 −22degree =6

(y 3 −2)(y 3 +11)=y 3 (y 3 +11)−2(y 3 +11)=y 6 +11y 3 −2y 3 −22=y 6 +9y 3 −22degree =6When we write a polynomial in standard form, the highest-degree term comes first and lowest-degree term as last.