Question

write the following QE in standard form y -5/y =3y-7​

Answer 1

Step-by-step explanation:

$y - \frac{5}{y} = 3y - 7 \\ \frac{ {y}^{2} - 5}{y} = 3y - 7 \\ {y}^{2} - 5 = 3 {y}^{2} - 7y \\ 2 {y}^{2} - 7y + 5 = 0 \\ 2 {y}^{2} - 5y - 2y + 5 = 0 \\ y(2y - 5) - 1(2y - 5) = 0 \\ (2y - 5)(y - 1) = 0 \\ y = \frac{5}{2} \: or \: 1$