write the following quadratic equation in standard form and then the write the values of a b and c
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(i) x^2-9=13x
now writing it in standard form
x^2 -13x -9=0
now the values of a,b nd c will be
a=1
b= -13
c= -9
(ii)2x^2=3x
in standard form
2x^2 - 3x =0
values of a,b nd c will be
a=2
b= -3
c=0
(iii) x + 5/x =-3
x^2 + 5. = -3
_______
x
x^2+5=-3x
x^2+3x+5=0. ( in standard form)
values of a,b,nd c will be
a=1
b=3
c=5
(iv)(x+4)(x-10)=0
x^2-10x+4x-40=0
x^2-6x-40=0. ( in standard form)
value of a,b,nd c will be
a=1
b=-6
c=-40
hope it helps!
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