Question

write the following quadratic equations in standard form and then write the valve of a,b,c:(x+4)(x-10)=0​

Answer 1

Answer:

Equation : x²-6x-40

a= 1

b= -6

c= -40

Answer 2

Answer:

${\boxed{x^{2}-6x+40=0}}$ is the standard form.

Nd   a = 1 ; b = -6 ; c = 40 .

Step-by-step explanation:

$(x+4)(x-10)=0\\=> x^{2}+4x-10x+40=0\\=> x^{2}-6x+40=0$

Comparing it with $ax^{2} +bx+c=0$ ;

a = 1 ; b = -6 ; c = 40 .