Question

write the following rational number in standard form
(A) 9 upon 36
(B)118 upon 272
(C)25 upon 625​

Answer 1

$1) \: \frac{9}{36} \\ \\ = \frac{9}{9 \times 4} \bf = \frac{1}{4} \\ \\ 2) \: \frac{118}{272} \\ \\ = \frac{2 \times 59}{2 \times 136} \bf = \frac{59}{136} \\ \\ 3) \: \frac{25}{625} \\ \\ = \frac{25}{25 \times 25} \bf = \frac{1}{25}$

Answer 2

$\huge\mathfrak\green{\underline{Explanation:-}}$

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In order to write a rational number in standard form, try to cancel out both the numbers.

Let's do it!

In case ( A ) :

$\sf =\dfrac{9}{36} \\\\ = \cancel{\dfrac{9}{36}}\\\\ =\dfrac{1}{4}$

Hence,

→ The standard form of 9/36 is 1/4.

Now,

In part ( B ), they have given three digit numbers. Nothing to worry! Apply the same method here too.

$\sf=\dfrac{118}{272}$

Try to cancel out numerator and denominator by the multiple of 3.

$\sf=\cancel{\dfrac{118}{272}}\\\\ =\dfrac{59}{136}$

Hence,

The standard form of 118/272 is 59/136.

Finally,

In the last part,

$\sf=\dfrac{25}{625}\\\\ =\cancel{\dfrac{25}{625}}\\\\ =\dfrac{1}{25}$

Hence,

The standard form of 25/625 is 1/25.

whoa! We have done so easily.

$\rule{200}2$