Question

write the following rational numbers in ascending and descending order:- -3/7, -3/2, -3/4, -2/9, -4/3​

Answer 1

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$\frac{3}{7} > \frac{ - 2}{9} > \frac{ - 3}{4} > \frac{ - 3}{2} > \frac{ - 4}{3}$

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Answer 2

The descending and ascending orders are as follows resp:

$\dfrac{-56}{252}>\dfrac{-108}{252}>\dfrac{-189}{252}>\dfrac{-336}{252}>\dfrac{-378}{252}\\\\\dfrac{-378}{252}<\dfrac{-336}{252}<\dfrac{-189}{252}<\dfrac{-108}{252}<\dfrac{-56}{252}$

Step-by-step explanation:

Since we have given that

$-\dfrac{3}{7},\dfrac{-3}{2},\dfrac{-3}{4},\dfrac{-2}{9},\dfrac{-4}{3}$

LCM of 7, 2, 4, 9, 3 = 252

So, it becomes,

$\dfrac{-3\times 36}{7\times 36}=\dfrac{-108}{252}$

$\dfrac{-3\times 126}{2\times 126}=\dfrac{-378}{252}$

$\dfrac{-3\times 63}{4\times 63}=\dfrac{-189}{252}$

$\dfrac{-2\times 28}{9\times 28}=\dfrac{-56}{252}$

$\dfrac{-4\times 84}{3\times 84}=\dfrac{-336}{252}$

So, the descending and ascending orders are as follows resp:

$\dfrac{-56}{252}>\dfrac{-108}{252}>\dfrac{-189}{252}>\dfrac{-336}{252}>\dfrac{-378}{252}\\\\\dfrac{-378}{252}<\dfrac{-336}{252}<\dfrac{-189}{252}<\dfrac{-108}{252}<\dfrac{-56}{252}$

# learn more:

-1/3,-2/9,-4/3 Write the following rational numbers in ascending order

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