Question

write the following relations as set of
ordered pairs and find which of them are
functions
1){(x,y) : y = 3x, x€ {1,2,3}, y€{3,6,9,12))
2) {(x,y) : y greater than x+1, X = 1, 2 and y = 2,4,6}
3){(x,y):x+y =3,x,y € (0, 1, 2, 3))​

Answer 1

Answer:

If 2x+3y+5z=10 and 81 xyz=100,where triplet x,y,z∈R

+

, then number  of ordered (x,y,z) is:

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