Write the following set as an interval: {x ∈ R ∶ − 1 3 < 2 − 7x ≤ 3 5 }
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Answer:
Given: −
3
x
≤
2
x
−1
3
1
<
6
1
Taking L.C.M. of 3,2 and 6 is 6.
−
3
x
×6≤
2
x
×6−
3
4
×6<
6
1
×6
−2x≤3x−8<1
⇒−2x≤3x−8 and 3x−8<1
⇒8≤3x+2x ⇒3x<1+8
⇒8≤5x ⇒3x<9
⇒
5
8
≤x ⇒x<3
∴ The solution set is {x:1.6≤x≤3,xϵR}
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