Math, asked by najlakv73, 6 months ago

write the following set in roster form
a) { x:x is a solution of the equation x^2 - 10x +16=0}​

Answers

Answered by subgb98
3

Answer:

A={8,-2}

Step-by-step explanation:

x²-10x+16=0

x²-8x-2x+16=0

x(x-8)+2(x-8)=0

x-8=0     and    x+2=0

x=8       and x=-2

so the set in set roster form

A={8,-2}

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