Write the following sets in roster form.
(iv) E = {x:x= 2n+1, -3
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Answered by
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Answer:
On putting n=1,2,3,... in x=2n+1, we get
x=3,5,7,...
Therefore, in roster form the given set is
{3,5,7,...}
hope it helps you!
Answered by
0
Answer:
{3,5,7...} this is answer
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