Write the following sets in the roaster from
(i) A = {x : x ∈ R, 2x + 11 = 15} (ii) B = {x | x^2 = x, x ∈ R}
(iii) C = {x | x is a positive factor of a prime number p}
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i) A= {2}
ii) B= {0,1}
iii) C= {1}
ii) B= {0,1}
iii) C= {1}
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Answer:
We know that the factors of the prime numbers are 1 and the number itself.
The whole number of factors of the prime number is 2.
Step-by-step explanation:
(i) Given: A = {x∶ x ∈ R,2x + 11 = 15}
To find: Roster form of given set
2x + 11 = 15
⇒ 2x = 15 – 11
⇒ 2x = 4
⇒ x = 2
So, A = {2}
(ii) Given: B = {x | x^2 = x,x ∈ R}
To find: Roster form of given set
x^2 = x
⇒ x^2 – x = 0
⇒ x(x – 1) = 0
⇒ x = 0 or 1
So, B = {0,1}
(iii) Given: C = {x | x is a positive factor of the prime number p}
To find: Roster form of given set
Only possible positive factors of the prime number p are 1 and p itself.
Hence,
x = 0 or p
So, C = {0,p}
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https://brainly.in/question/5323793
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