Question

Write the following sets in the roster form.

(i) A = {x | x is a positive integer less than 10 and 2x – 1 is an odd number}

(ii) C = {x : x2 + 7x – 8 = 0, x ∈ R}​

Answer 1

Answer:

your answer is in the attachment

Answer 2

$x is a positive integer according to question and is less than 10. Now, while substituting positive values less than 10 in 2x - 1, the answers we may get are : 1, 3, 5, 7, 9, 11, 13, 15, 17. All the results we get are odd. (ii) x² + 7x - 8 = 0, Solving the Given quadratic equation$

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