Question

Write the following terminating decimals in the form of p/q , q≠0 and p, q are co-primes
(i) 15.265 (ii) 0.1255 (iii) 0.4 (iv) 23.34 (v) 1215.8
What can you conclude about the denominators through this process?

Answer 1

Co prime number: Two numbers which have only 1 as common factor are said to be co-prime.

(i) 15.265 =15265/1000=3053/200

(ii) 0.1255 =1255/10000=251/2000

(iii) 0.4=4/10=2/5

(iv) 23.34=2334/100=1167/50

(v) 1215.8=12158/10=6079/5

Conclusion: Denominators are multiple of 5

Answer 2

Answer:

(i) 3051/200 (ii) 251/2000, (iii) 2/5, (iv) 1167/50 (v) 6079/5

Step-by-step explanation:

Given: Numbers are (i) 15.265 (ii) 0.1255 (iii) 0.4 (iv) 23.34 (v) 1215.8.

To write them in the form of p/q , q≠0 and p, q are co-primes.

(i) 15.265

In p/q form 15.265 can be written as:

15.265=15265/1000

          = 3051/200

Here p=3051 & q=200 ; q$\neq 0$.

(ii) 0.1255

In p/q form 0.1255 can be written as:

0.1255=1255/10000

          =251/2000

(iii) 0.4

In p/q form 0.4 can be written as:

0.4=4/10

    =2/5

(iv) 23.34

In p/q form 23.34 can be written as:

23.34=2334/100

        =1167/50

(v) 1215.8.

In p/q form 1215.8 can be written as:

1215.8=12158/10

         =6079/5

The denominator in all the five fractions is the multiples of 5.

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