write the formation of BCl3 by valence bond theory
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To form bonds with chlorine, boron will require three unpaired electrons. ... Each sp2 hybrid orbitals will contain unpaired electrons that will overlap with the unpaired electron in chlorine's 3p orbital. Three σsp-p bonds are formed between boron's half-filled sp2 hybrid orbitals and three chlorine atoms.
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Yes BCl3 is an electron-deficient compound. As boron has three valence electrons, it forms 3 single bonds with chlorine, In total the boron atom gives 6 electrons in the outermost shell. It still lacks 2 electrons to complete its octet.
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