write the formula for 1³+2³+......+n³=?
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1³=1=1²
1³+2³ = 9=3²
1³+2³+3³=36=6²
1³+2³+3³+4³=100=10²
1³+2³+3³+4³+5³=225=15²
So it’s the same as the square of the triangular numbers.
The triangular numbers are (n)(n+1)/2 so the sum of the first n cubes is [(n)(n+1)/2]².
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