Question

Write the formula for calculating amount
with compound interest and explain the
terms in the formula?​

Answer 1

Answer:

A = P(R/100)^n

Step-by-step explanation:

where

A is amount

P is principal

R is rate

n is no.of years

Answer 2

Compound interest is calculated by multiplying the initial principal amount by one plus the annual interest rate raised to the number of compound periods minus one.

According to formula,

A = P( 1 +r/100)n

Where A is total amount after n years, r is the rate. P is the amount initially

Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)

Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"

Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)

Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)

Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2

Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)

Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2

Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.

Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.now,

Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.now,amount payable after 5years

Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.now,amount payable after 5yearsA5 =10,000(1.1)^5

Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.now,amount payable after 5yearsA5 =10,000(1.1)^5=16, 105.1 Rs