Question

write the formula for maximum height attained by a projectile​

Answer 1

Answer

if α = 45°, then the equation may be written as: hmax = h + V₀² / (4 * g) and in that case, the range is maximal if launching from the ground (h = 0). if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.

Answer 2

$\bold{H_{max}=\dfrac{u^2\sin^2θ}{2g}}$