Question

Write the formula for maximum work for isothermal reversible process.​

Answer 1

Answer:

Given: m = 42.8 × 10-2 kg, P1 = 15.15 × 105 Nm-2, Maximum work of expansion = W = – 17.33 kJ = – 17.33 × 103 J, T = 293 K, R = 8.314 J K-1 mol-1, P2 =? To Find: Final Pressure =? Example – 05: 3 moles of an ideal gas are compressed isothermally and reversibly at 22° C to a volume 2L when work done is 2.983 kJ.

Explanation:

Answer 2

Answer:

this is your answer bro

Explanation:

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