Question

write the formula for ten ( a + b + c)​

Answer 1

Step-by-step explanation:

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the formula is in the photograph

Answer 2

Answer:

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Step-by-step explanation:

a² – b² = (a-b)(a+b)

(a+b)² = a² + 2ab + b²

(a-b)² = a² – 2ab + b²

a² + b² = (a-b)² +2ab

(a+b+c)² = a²+b²+c²+2ab+2ac+2bc

(a-b-c)² = a²+b²+c²-2ab-2ac+2bc

a³-b³ = (a-b) (a² + ab + b²)

a³+b³ = (a+b) (a² – ab + b²)

(a+b)³ = a³+ 3a²b + 3ab² + b³

(a-b)³ = a³- 3a²b + 3ab² – b³

“n” is a natural number, an – bn = (a-b) (an-1 + an-2b +….bn-2a + bn-1)

“n” is a even number, an + bn = (a+b) (an-1 – an-2b +….+ bn-2a – bn-1)

“n” is an odd number an + bn = (a-b) (an-1 – an-2b +…. – bn-2a + bn-1)

(am)(an) = am+n (ab)m = amn