Question

write the formula for1²+2²+......+n²=?​

Answer 1

${\huge{\boxed{\purple{\mathcal{ANSWER}}}}} \\{1}^{2} + {2}^{2} + {3}^{2} + ........ + {n}^{2} \\ = \frac{n(n + 1)(2n + 1)}{6} \\ where, \: n \: is \: the \: number \: of \: terms$

n(n+1)(2n+1)/6 is the right answer.