Question

Write the formula of any five Potassium Compounds?

Answer 1

KCl, KMnO4, K2Cr2O7,KOH,K2O are five potassium compound.

thanks....

Answer 2

➶➶➶➶➶[ ANSWER ]➷➷➷➷➷

⚫Pottasium(K) is a metal that had being placed in group 1 and period 4.

◼Atomic number of potassium is 19.

◼so, it's electronic configuration will be

➡2,8,8,1.

◼According to which it's vakency is +1.

If it will form compound by losing its one electron to be stable like nearest noble gas Argon (2,8,8).

◼According to its periodic properties the compound it will form will be

✳ By Electrovalent bond of ionic in nature.

✳Mostly solid

✳Basic in nature.

◽Like while forming a chloride,

Chlorine to be stable like nearest noble gas argon (2,8,7) will gain one electron from pottasium.

▶

${K}^{ + 1 } \longrightarrow{Cl}^{ - 1}$

(2,8,8,1)......(2,8,7)

▶KCl(pottasium chloride) .

where the formed compound is solid and basic in nature.

◽While forming an oxide ,

Oxygen to be stable like nearest noble gas neon gains two electrons .Since, potassium has only one valence electrons ,two atoms of potassium formed the compound.

▶

${K}^{ + 1} \longrightarrow {O}^{ - 2}\longleftarrow{K}^{ + 1}$

(2,8,8,1).....(2,8,6)....(2,8,8,1)

▶K2O (Potassium oxide).

where the compound is solid and strongly basic in nature.

◽While forming a nitrate,

Nitrogen radical has one valence electron so to be stable it gains one electron from pottasim.

▶

${K}^{ + 1} \longrightarrow {NO_3}^{ - 1}$

(2,8,8,1).

➡KNO3.

where the formed compound is a ionic compound and solid.

◽While forming a carbonate,

Carbonate radical has valence electron -1 ,so to be stable it gains one electron from potassium .

▶

${K}^{ + 1} \longrightarrow{HCO_3}^{ - 1}$

(2,8,8,1).

▶KHCO3

where the formed compound is white solid and ionic in nature.

⚫Other compound of potassium are :-

➡KNO2(Pottasium nitrite)

➡KMnO4(Potassium permanganate)

➡KAlO2(Pottasium aluminate )

➡KBr(Pottasium bromide)

➡KOH(Pottasium hydroxide) .

✨✨✨HOPE IT HELPS ✨✨✨