Question

write the formula of the ionic compound where both the cation and the anion posses helium - like electronic configuration ?​

Answer 1

✌️❤️ $\huge\red{A}\pink{N}\orange{S}\green{W}\blue{E}\gray{R}$ ❤️✌️

Formula of ionic compound is AB

2

.

A cations are present at the alternate corners. There are 8 corners out of which 4 have A cation. Each corner contributes one eighth to the unit cell. Hence, total number of A cations present per unit cell =

8

1

×4=0.5.

B anion is present on the body of the diagonal. It fully contributes to the unit cell.

Hence, total number of B cations present per unit cell is 1

The ratio of number of A cations to number of B cations is

0.5:1 or 1:2

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