Question

Write the formula of the product formed when the element at atomic number 19 combines with the element b (atomic number 17). Draw its electron dot structure. What is the nature of the bond formed

Answer 1

May be this could help u .

Answer 2

a) The formula of the product formed when the element at atomic number 19 combines with the element b (atomic number 17) is $KCl$

b) The nature of the bond is ionic.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Electronic configuration of element with atomic number 19 containing 19 electrons

$[K]:19:1s^22s^22p^63s^23p^64s^1$

Potassium atom will loose one electron to gain noble gas configuration and form potassium cation with +1 charge.

$[K^{+}]:18:1s^22s^22p^63s^6$

Electronic configuration of element with atomic number 17 containing 17 electrons

$[Cl]:17:1s^22s^22p^63s^23p^5$

Chlorine atom will gain one electron to gain noble gas configuration and form chloride ion with -1 charge.

$[Cl^-]:18:1s^22s^22p^63s^23p^6$

The oppositely charged ions combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $KCl$.

Electron dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the electron dot structure the valance electrons are shown by 'dot'.

The given molecule is $KCl$

As we know that potassium has '1' valence electron and chlorine has '7 ' valence electrons.

Therefore, the total number of valence electrons in  = 1 + 1(7) = 8

The electron dot structure of $KCl$ is shown below.

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