Math, asked by ironmwn255, 9 months ago

Write the formula to find compound interest and also explain the terms in it

Answers

Answered by camjayasudha
1

Answer:

C.I = P × {(1-i)^n - 1}

Step-by-step explanation:

C.I = compound interest

P = Principal amount

i = r/100

r = interest % rate (or) rate of interest

n = no.of years (the principal deposited )

Answered by shaider
3

Compound interest is calculated by multiplying the initial principal amount by one plus the annual interest rate raised to the number of compound periods minus one.

According to formula,

According to formula,An = P( 1 +r/100)

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initially

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.now,

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.now,amount payable after 5years

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.now,amount payable after 5yearsA5 =10,000(1.1)^5

According to formula,An = P( 1 +r/100)Where A is total amount after n years, r is the rate. P is the amount initiallyAn =10, 000( 1 + 10/100)=10,000( 1+0.1)"=10,000(1.1)An =10,000(1.1)now, put n = 1 A1 =10, 000(1.1), put n =2, A2 =10,000(1.1)2in the same way, A3 =10, 00(1.1)you can see that A2/A1 = A3/A2so, {An} is in Geometric progression.now,amount payable after 5yearsA5 =10,000(1.1)^5=16, 105.1 Rs

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