Write the formula to find the sum of the first n terms of an arithmetic progression whose first term is a and last term is a n
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sum of n terms of an AP is
S= (n/2)[a+(n-1)d]
where S is sum , n is number of terms, a is first term , d is the difference
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Answer:
n/2(2a+(n-1)d)
Step-by-step explanation:
given a=a
n=an
hence the formula to find the sum of these arithemetic progression is
Sn=n/2(2a+(n-1)d)
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