write the four quantum numbers for an electronic configuration 4s1
Answers
Answered by
4
Answer:
given differentiating electron is 4s1
the four quantum numbers is
- n=4
- l=0 [for s-orbital l=0
for p-orbital l=1
for d-orbital l=2
for f-orbital l=3]
- =0 as m=-l to +l values
- =+1/2
hope this helps you
mark me as the brainliest
Similar questions