Physics, asked by gramsingh076, 8 months ago

write the four quantum numbers for an electronic configuration 4s1 ​

Answers

Answered by suhasinipandraju
4

Answer:

given differentiating electron is 4s1

the four quantum numbers is

  • n=4
  • l=0        [for s-orbital   l=0

                       for  p-orbital   l=1

                        for d-orbital     l=2

                        for f-orbital      l=3]

  •   m_{l}=0  as  m=-l to  +l  values
  •   m_{s}=+1/2

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