write the four quantum numbers for the differentiating electron of sodium (Na) atom?
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Answer:
Explanation:
Electronic configuration of Na atom=1s 2 2s 2 2p 6 3s 1
3s 1 e − is differentiating electron
For 3s 1 e − ; n=3,l=0,m=0,m s = 2 +1 or 2 −1
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Sodium (Na) Z= 11
electronic configuration 1s2 2s2 2p6 3s1
the differentiating electron is in 3s
the four quantum number is
n - 3
l - 0
m - 0
s - 1/2
i hope it will help you
regards.
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