write the four quantum numbers for the differentiating electron of sodium(Na)atom? ( with clear explanation please)
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Answer:write the four quantum numbers for the differentiating the electron sodium(Na)
Explanation:
The atomic number(Z) of Na is 11.
So the electronic configuration is,
1s2 , 2s2 , 2p6 , 3s1.
Here we consider 3s1.
The four quantum numbers are,
n=3,
Because in 3s1, "the principle quantum number(n)" is 3.
I=0,
Because in "angular-momentum quantum number" , s=0,p=1,d=2,f=3.
So here in 3s1, s=0.
Ml=0,
Because l=0,so Ml=0.
Ms= -1/2
Because,according to"Spin quantum number" in electronic configuration last electron is single but not bonded (3s1) so it is -1/2.
So,
n=3,
l=0,
Ml=0,
Ms= -1/2.
Thank you, I think it will be useful
for you.
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