Question

write the four quantum numbers for the differentiating electron of sodium {na} atom?

Answer 1

Sodium (Na) Z= 11 
electronic configuration 1s2 2s2 2p6 3s1
the differentiating electron is in 3s

the four quantum number is 

n    - 3
l     - 0
m   - 0
s    - 1/2

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Answer 2

Answer:write the four quantum numbers for the differentiating the electron sodium(Na)

Explanation:

The atomic number(Z) of Na is 11.

So the electronic configuration is,

1s2 , 2s2 , 2p6 , 3s1.

Here we consider 3s1.

The four quantum numbers are,

n=3,

Because in 3s1, "the principle quantum number(n)" is 3.

I=0,

Because in "angular-momentum quantum number" , s=0,p=1,d=2,f=3.

So here in 3s1, s=0.

Ml=0,

Because l=0,so Ml=0.

Ms= -1/2

Because,according to"Spin quantum number" in electronic configuration last electron is single but not bonded (3s1) so it is -1/2.

So,

n=3,

l=0,

Ml=0,

Ms= -1/2.

Thank you, I think it will be useful

for you.