Question

write the four quantum numbers for the differentiating electron of Aluminium


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Answer 1

#n =3#

#l = 1 #

#m = -1#

#s = +1/2#

Explanation:

You are very close :), just the #m_l# or what I simply call #m# is incorrect. The variable #m# has allowed values from #-l <= m <= +l# and it represents the shell that the last electron of Aluminum is located. If you were to draw the electron energy diagram for it, you find that it is in the first box, or shell, thus since #m# can in this case be -1, 0, 1, it is -1.