Question

Write the fourth term of an arithmetic sequence with first term 25 and common difference 7​

Answer 1

Answer:

The first step is to find the common difference. Subtract the lower term from the higher term, and divide by the difference of the indices of the term.

d = (25–13)/(10–4)

d= 12/6

d=2

Now to find the first term use the following:

13 - (4–1)2

13 -3(2)

13–6

7

The 17th term is equal to the first term plus the difference of 17 and 1.

7+(17–1)2

7+(16)2

7+32

39

Answer 2

Answer:

In the AP, 4th term = a+3d = 18 …(1)

The 6th term = a+5d = 28 …(2)

Subtract (1) from (2)

2d = 28–18 = 10 or d = 5.

From (1), a = 18 - 3x5 = 18–15 = 3.

So the 2nd, 3rd and 5th terms are : 8, 13 and 23, respectively. The common difference between consequent terms is 5.

Step-by-step explanation:

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