Question

write the full step
Std VI
Sub: Maths
Ls Name: Bank and Simple Interest
Solve.
1)What will be the interest on 315,000 principal
at the rate of 9 p.c.p.a?
2) Principal == 800, Amount = 840.Find rate of
interest and interest of 1 year.
3) Rate of interest = 7%, Interest of 1 year =R42.
Find principal and amount.​

Answer 1

Answer:

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Answer 2

➤ Correct Question :-

1. What will be the interest on ₹315000 of principle in 1 year at rate of 9% ?
2. Find the interest and rate of interest if principal is ₹800 and amount is ₹840 and time is 1 year.
3. Find the principle and amount if rate of interest is 7% and interest of 1 year is ₹42.

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★ How to do :-

Here, we are given with three simple interest sums. We should find the simple interest in the first one and rate of interest and simple interest in second one and principle and total amount at the third one. There are many formulas related to simple interest which helps us to solve these problems. Some of them are given below.

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➤ Solution (1) :-

Simple Interest :-

${\tt \leadsto \dfrac{315000 \times 9 \times 1}{100}}$

${\tt \leadsto \dfrac{\cancel{315000} \times 9 \times 1}{\cancel{100}} = 3150 \times 9 \times 1}$

${\tt \leadsto 3150 \times 9 = \boxed{\tt Rs \: \: 28350}}$

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➤ Solution (2) :-

Simple Interest :-

${\tt \leadsto 840 - 800}$

${\tt \leadsto Rs \: \: 40}$

Rate of interest :-

${\tt \leadsto \dfrac{40 \times 100}{800 \times 1}}$

${\tt \leadsto \dfrac{40 \times \cancel{100}}{\cancel{800} \times 1} = \dfrac{40 \times 1}{8 \times 1}}$

${\tt \leadsto \cancel \dfrac{40}{8} = \boxed{\tt 5 \bf\%}}$

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➤ Solution (3) :-

Principle :-

${\tt \leadsto \dfrac{42 \times 100}{7 \times 1}}$

${\tt \leadsto \dfrac{\cancel{42} \times 100}{\cancel{7} \times 1} = \dfrac{6 \times 100}{1 \times 1}}$

${\tt \leadsto \cancel \dfrac{600}{1} = \boxed{\tt Rs \: \: 600}}$

Total amount :-

${\tt \leadsto 600 + 42}$

${\tt \leadsto Rs \: \: 642}$

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$\dashrightarrow$ Formulas used :-

Simple Interest :- ${\boxed{\tt\dfrac{P \times R \times T}{100}}}$

Principle :- ${\boxed{\tt\dfrac{SI \times 100}{R \times T}}}$

Rate of interest :- ${\boxed{\tt\dfrac{SI \times 100}{P \times T}}}$

Time :- ${\boxed{\tt\dfrac{SI \times 100}{P \times R}}}$