write the general term in the expansion of (x^2-y)^6
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Answer:(x^12+y^6)(x^12-y^6)
Step-by-step explanation:
(x^2-y)^6 = (x^2*6-y^1*6)
= (x^12-y^6)
(X^a-Y^b) = (X^a-Y^b)(X^a+Y^b)
(x^12-y^6) = (X^12-Y^6)(X^12+Y^6)
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