Math, asked by Alpha373, 10 months ago

write the general term in the expansion of (x^2-y)^6​

Answers

Answered by Dhanush455
4

Answer:(x^12+y^6)(x^12-y^6)

Step-by-step explanation:

(x^2-y)^6​  =  (x^2*6-y^1*6)

                =  (x^12-y^6)

(X^a-Y^b)  =  (X^a-Y^b)(X^a+Y^b)

(x^12-y^6)  =  (X^12-Y^6)(X^12+Y^6)

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