Question

Write the given quadratic equation in standard form and also write the

values of a, b and c .

4y2 – 3y = -7​

Answer 1

Answer:

• Remember that in standard form, the equation is written in the form ax2 + bx + c = 0. 3x + x2 = 6 becomes 3x + x2 – 6 = 0, so the standard form is x2 + 3x – 6 = 0. This means the correct answer is a = 1, b = 3, and c = −6.

Answer 2

$\large \underline{\underline{\tt Given}} :$

• Quadratic equation = 4y² - 3y = - 7

$\large \underline{\underline{\tt To \: Find}} :$

• Write equation in standard form.
• Write values of a, b and c.

$\large \underline{\underline{\tt Solution \: Required}} :$

Note : In basics standard form of quadratic equation is written in the form of ay² + by + c = 0, where a ≠ 0.

The equation given over here is :

4y² - 3y = - 7

So, it's standard form ought to be :

$\sf \dashrightarrow 4y^{2} + (- 3)y + 7 = 0$

Here,

• a = 4
• b = - 3
• c = 7

Thus in the quadratic equation 4y² - 3y = - 7 the values of a , b and c are 4 , -3 and 7 respectively .