Question

write the greatest 4 digit number and exprex it in the form of its prime factors? ​

Answer 1

Answer:

We will see the prime factors of 9999 to answer this question. Explanation: The prime factors of 9999 are 3,3, 11, and 101. We can express 9999 as the product of its prime factors, that is, 9999 = 3² × 11 ×101.

Answer 2

To Find :-

Express the greatest 4 digit number as product of its prime

Solution :-

At first you should know what is the greatest 4 digit number . The greatest 4 digit number is 1000

So , Writing it in the form of product of its Primes we have ;

$\quad \qquad \leadsto \bf 1000$

${ : \implies \quad { \sf { 2 × 500 }}}$

${ : \implies \quad { \sf { 2 × 2 × 250 }}}$

${ : \implies \quad { \sf { 2 × 2 × 2 × 125 }}}$

${ : \implies \quad { \sf { 2 × 2 × 2 × 5 × 25 }}}$

${ : \implies \quad { \sf { 2 × 2 × 2 × 5 × 5 × 5 }}}$

Now In form of powers we can write it as

${ : \implies \quad { \bf 2³ × 5³ }}$

Note :- Refers the attachment for prime Factorization

Henceforth , The Required Answer is 2³ × 5³ !