Question

write the greatest and the smallest digit in the blankplace so that the no will form divisible by 3​

Answer 1

Answer:

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Answer 2

Provide the blank space please and the rest numbers

you can do this answer yourself only...

the process is

Let a number 321_7.

Let the digit in blank space be x.

So the sum of the digits =3+2+1+x+7=13+x

The nearest number which is divisible by three is 15.

So 15-13=2.

HENCE THE DIGIT IS 2