Question

Write the greatest number of 6 digits . Divide it by the product of 4and 7.

Answer 1

Product of 4 and 7 ⇒ 4 × 7

                                ⇒ 28

Greatest 6 digit number = 999999

On dividing 999999 by 28, we get 7 as reminder

                 28 ) 999999 ( 35714

                         999992

                        -

                       ________

                                   7

                        _______

therefore,

Required number is 999999 - 7

Required number is 999992

the greatest 6 digit number which is divisible by the product of 4 and 7 is 999992

$\:$