Write the greatest number of seven digits by using
0, 1, 2, 3 and 4.( Repetition is allowed)
Answers
Answered by
2
Step-by-step explanation:
hlo mate here's your answer
180
53
Two or more than two digit number will be divisible by 4 if its last two
digit are divisible by 4 so we need the number of the form 04, 08, 12,
24, 28, 32, 40, 48, 80, 84, 92. There are twelve cases out of which in 5
cases like 04, 08, 20, 40, 80, total numbers are
=
5×
5!
and numbers in other 7 cases are
4×
4!×
7
Number of favorable cases are
=
5×
5!+
4×
7×
4!
=
(25+28)4!=
53×
4!
Total number of 7 digit number
=
7!−
6!=
6.6!
∴
Required probability
=
6×6×5×4!
53×4!
=
180
53
I hope its help you mark as brainlist plz ok
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