Question

write the hcf of 18a³b²c and 36a²bc​

Answer 1

18a³b²c = 18×a³×b²×c

36a²bc = 36×a²×b×c

HCF of 18 and 36 = 18

of a³ and a² = a²

of b² and b = b

of c and c = c

so total HCF = 18a²bc

HCF of a³ and a² = a²

because a³ = a×a×a

a² = a×a

HCF of a×a×a and a×a

= a×a = a²

as HCF is highest common factor

and a×a is the highest common factor