Write the HCF of 270, 945
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Answered by
2
Answer:
Find the prime factorization of 270
270 = 2 × 3 × 3 × 3 × 5
Find the prime factorization of 945
945 = 3 × 3 × 3 × 5 × 7
To find the HCF, multiply all the prime factors common to both numbers:
Therefore, HCF = 3 × 3 × 3 × 5
HCF = 135
thank you
Answered by
0
Answer:
factors of 270= 2x5x3³
factors of 945 = 5x3³x7
HCF= 5.3³= 5x27= 135
hope it helps..
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