Question

write the hcf of 40,56,60

Answer 1

So ur answer is here i hope so it helps you

Answer 2

$We \:have ,$

$40 = 2\times 2 \times 2 \times 5 = 2^{3} \times 5^{1}\\ 56 = 2 \times 2\times 2 \times 7 = 2^{3} \times 7^{1} \\ 60 = 2\times 2 \times 3 \times 5 = 2^{2} \times 3^{1} \times 5^{1}$

$HCF (40,56,60) = 2^{2}$

/* Product of the smallest power of each common prime factors of the numbers */

Therefore.,

$\red{HCF (40,56,60)}\green {= 4 }$

•••♪