Question

write the integers from -100 to +100 integer​

Answer 1

Step-by-step explanation:

Integers between 100 and 200 divisible by 6 are-

102,108,114,...198

Above series is in A.P. with first term 102 and common difference 6.

a=102

d=6

Last term l=198

t

n

=a+(n−1)d

198=102+(n−1)6

(n−1)6=198−102=96

(n−1)6=96

n−1=16

⟹n=17

∴Sum=

2

n

[a+l]=

2

17

[102+198]

=

2

17

×300=150×17=2550