Question

write the integral zero of the polynomial (x-3)(x-7)​

Answer 1

Answer:

3  and 7

Step-by-step explanation:

let q(x) = (x-3)(x-7)

Zeroes of q(x) = (x-3)(x-7)

            Put    q(x) = 0

                 ⇒ (x-3)(x-7) = 0

                    ⇒x = 3 or x = 7

zeroes are 3 and 7

Answer 2

Answer:

Zero of p(x) =( x-3)(x-7)

Put p(x) =0

(X-3) ( x-7)=0

Thus, x=3 orx=7

Here you go hope it helps you ❤️