write the integral zeroes of the following polynomials (ii) (x+1) (3x+2)
Answers
Answered by
14
Answer:
-1 & -2/3.....................
Answered by
22
Answer:
p(x)=(x+1)(3x+2)
p(x)=0
=(x+1)(3x+2)=0
=x+1=0 or 3x+2=0
=x=-1 or x=-2/3
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